50y^2-225y-7=0

Solution for 50y^2-225y-7=0 equation:

50y^2-225y-7=0

a = 50; b = -225; c = -7;
Δ = b2-4ac
Δ = -2252-4·50·(-7)
Δ = 52025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{52025}=\sqrt{25*2081}=\sqrt{25}*\sqrt{2081}=5\sqrt{2081}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-225)-5\sqrt{2081}}{2*50}=\frac{225-5\sqrt{2081}}{100}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-225)+5\sqrt{2081}}{2*50}=\frac{225+5\sqrt{2081}}{100}
$